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How to calculate steel quantity pdf

There're two parts. First part is base (denoted by A) and second part is stem (denoted by B). Therefore, retaining wall volume = base slab volume + stem volume, A) Base slab, Base slab length = 4 m, Base slab breadth = 12 m, Base slab thickness = 300 mm = 0.300 m, Base slab volume = length x breadth x height = 4 x 12 x 0.300 = 14.4 m 3,.

So, now we have to find two-parameter, Volume and Density Let us first calculate the Volume of Hollow Steel Pipe The Volume of Hollow Steel Pipe = [3.14 (0.2² - 0.19²) x 3] / 4 = 0.0091845 Cubic meter We know, the Density of Steel is 7850 kg/m³ Weight of Hollow Steel Pipe Volume of Hollow Steel Pipe x Density of Steel = 0.0091845 x 7850 = 72.098 KG. Steel Quantity Calculation (Cutting length) main bar: formula = (l) + (2 x ld) + (1 x 0.42d) - (2 x 1d), where l = clear span of the slab, ld = development length which is 40 d (where d is diameter of bar), 0.42d = inclined length (bend length), 1d = 45° bends (d is diameter of bar) first calculate the length of "d". Like this post?.

2015. 9. 15. · or placed. For the purpose of calculating the total length of the steel bars, at present, the practice is – the length of each bar is measured and then added up. This is.

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Multiply your total square footage of usable space (80,000) by your facility's clear height to determine your warehouse's storage capacity in cubic feet. Going with our example, if your building's clear height is 25 feet, it has a total storage capacity of 2,000,000 cubic feet. The reason you must convert your warehouse's total storage.

You can create a new job and import the project drawings in PDF/TIF/DWG format. After that, scale the drawing manually or by selecting a pre-defined scale from the options panel. Finally, use the digitizing feature to draw lines, areas, polygons in order to calculate the lengths, areas, and volumes of various items..

For example, let's calculate the weight in steel of a bar with length 1 meter and diameter of 20 mm. The volume of the steel bar is the product of the area of the cross-section and the length: π x r 2 x l = 3.1416 x 10 2 x 1000 = 314,160 mm 3 = 314.16 cm 3 (r = 1/2 x diameter, l = 1 m = 1000 mm).

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